what are the concentration of h3o+(hydronium ion) and oh-(hydroxide ion) in pure water at 298 K?
Answers
Answer:
The concentration of h30 ^ + ions pure water 10 ^ - 6mol dm^ - 3
Concept:
The concentration of a solute in a solution is the ratio of the solute to the solvent or total solution. Concentration is often represented as mass per unit volume. However, solute concentration can also be represented in moles or volume units.
Given:
Pure water at 298 K.
Find:
What is the concentration of H₃O⁺ (hydronium ion) and OH⁻ hydroxide ion) in pure water at 298 K?
Solution:
The dissociation of the hydronium ion in pure water at 298 K is as follows below:
H₃O⁺ ⇔ OH⁻ + H₂
We know that pOH + pH = 14
So, [OH⁻] + [H⁺] = 10⁻¹⁴
10⁻⁷ + 10⁻⁷ = 10⁻¹⁴
Thus, [H₃O⁺] = [OH⁻] = 10⁻⁷ g ion/liter
Hence, the concentration of H₃O⁺ (hydronium ion) and OH⁻ (hydroxide ion) in pure water at 298 K is 10⁻⁷ g ion/liter.
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