Question

What are the coordinates of the image of vertex C after a dilation with center (0, 0) and scale factor 2?


A.C’(3, 4)
B.C’(4, 6)
C.C’(6, 2)
D.C’(6, 4)

Answer 1

Given :  ABCD a trapezium

A ( - 2 , 6)

B ( 3 , 6)

C ( 3 , 2)

D ( - 4 ,2 )

dilation with center (0, 0) and scale factor 2

To Find : Coordinates of C'   ( Coordinate of C after Dilation )

A.C’(3, 4)

B.C’(4, 6)

C.C’(6, 2)

D.C’(6, 4)

Solution:

A ( - 2 , 6)

B ( 3 , 6)

C ( 3 , 2)

D ( - 4 ,2 )

dilation with center (0, 0) and scale factor 2

A' ( - 2 x 2 , 6 x 2)

B' ( 3x 2 , 6x 2)

C' ( 3x 2 , 2x 2)

D' ( - 4x 2 ,2x 2 )

A'  = ( - 4 , 12)

B' = ( 6 , 12)

C' ( 6 , 4)

D' = ( - 8 , 4)

coordinates of the image of vertex C after a dilation with center (0, 0) and scale factor 2  = C’(6, 4)

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