Question

What are the coordinates of the mid point a(5,-2) B(7,10)

Answer 1

$\huge { \underline{ \underline{ \mathfrak{ \blue{answer : - }}}}}$

Formula for mid point:-

$\huge \boxed{ (\frac{x_1 + x_2}{2} ,\frac{y_1 + y_2}{2} )}$

Given:-

A(5,-2) B(7,10)

$\huge \bf \longmapsto \: x_1 = 5 \\ \\ \huge \bf \longmapsto \: x_2 = - 2 \\ \\ \huge \bf \longmapsto \: y_1 = 7 \\ \\ \huge \bf \longmapsto \: y_2 = 10$

Substitute in Formula:-

$\huge \bf \longmapsto \: \frac{5 - 2}{2} , \frac{7 + 10}{2} = ( \frac{3}{2} , \frac{17}{2} )$

Answer 2

$\bf\huge\blue{\underline{\underline{ Question : }}}$

What are the coordinates of the mid point A(5,-2) B(7,10).

$\bf\huge\blue{\underline{\underline{ Solution : }}}$

★ Given that,

• A(5,-2)
• B(7,10)

★ To find,

• Mid - point.

★ Formula :

$\boxed{\tt{ Mid-point : \Bigg(\dfrac{ x_{1} + x_{2}}{2} , \dfrac{y_{1} + y_{2}}{2} \Bigg)}}$

• x1 = 5 ; y1 = - 2
• x2 = 7 ; y2 = 10

$\bf\:\implies \Bigg( \dfrac{ 5 + 7}{2} , \dfrac{- 2 + 10}{2}\Bigg)$

$\bf\:\implies \Bigg( \dfrac{12}{2} , \dfrac{8}{2}\Bigg)$

$\bf\:\implies (6,4)$

$\underline{\boxed{\rm{\purple{\therefore Mid-point\:of\:A(5,-2) ; B(7,10) \:is\: (6,4).}}}}\:\orange{\bigstar}$