What are the coordinates of the point 3/4 of the way from A toB?
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Answer:
( -3 , 4)
–
4
Step-by-step explanation:
Let P be the point which is three-fourth of the way from A(3,1) to B(−2,5).
∴AP:AB=3:4
AB=AP+PB
∴
AB
AP
=
(AP+PB)
AP
=
4
3
⇒4AP=3AP+3PB
⇒4AP−3AP=3PB
⇒AP=3PB
$$\Rightarrow \dfrac{AP}{AB} = \dfrac{3}{1}$$
∴ The ratio m:n=3:1
x
1
=3,y
1
=1,x
2
=−2,y
2
=5
∴ By Section formula x=
m+n
mx
2
+nx
1
∴x=
3+1
3×−2+1×3
∴x=
4
−6+3
∴x=
4
−3
And
∴ By Section formula y=
m+n
my
2
+ny
1
∴y=
3+1
3×5+1×1
∴y=
4
15+1
∴y=4
Hence the co-ordinates of P are ( -3 , 4)
–
4
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