Question

What are the coordinates of the point located 3 units to the left of the y-axis and 4 units above the x-axis?

Answer 1

$\sf ⋆ \star \red {Question! } \star⋆$

What are the coordinates of the point located 3 units to the left of the y-axis and 4 units above the x-axis?

$\huge\star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

It will be (-3,4)

hope it helps you...

Answer 2

Answer:

The coordinates of the point located 3 units to the left of the y-axis and 4 units above the x-axis = (-3,4)

Step-by-step explanation:

To find,

The coordinates of the point located 3 units to the left of y axis and 4 units above the x-axis.

Solution:

Recall the concepts:

The X and Y axes intersect at the point O(0,0) and divide the cartesian plane into four equal parts called quadrants.

Quadrants 1 and 2 lies above the X axis and 3 and 4 lies below the X axis.

Also, quadrants 1 and 4 lies to the right of the Y axis, and 2 and 3 lie on the left of the Y axis.

Here, the given point lies on the left of the Y axis and above the X axis, the only quadrant that satisfies this condition is the 2nd quadrant.

We know, that in the second quadrant x coordinate is negative and the y coordinate is positive.

Since the point is 3 units to the left of the Y axis, the x coordinate of the point = distance of the point from the Y axis  = 3

Also, since the point lies in the second quadrant,  x co-ordinate = -3

Since the point is 4 units above the X axis, the y coordinate of the point = distance of the point from the X axis= 4

Also, since the point lies in the second quadrant, the y co-ordinate = 4

∴ The coordinates of the point located 3 units to the left of the y-axis and 4 units above the x-axis = (-3,4)

#SPJ3