what are the coordinates of the point of intersection of two lines 3x+2y=0 and
2x-y=0
Answers
Answered by
1
Answer:
sorrryyyyy i dont know
Answered by
1
Answer:
Line passing through point of intersecting of L
1
,L
2
is given by L
1
+λ
2
=0
⇒(3x+2y+4)+λ(2x+5y−1)=0
⇒x(3+2λ)+y(2+5λ)+4−λ=0
Distance of (2,−1) to this line,
∣
∣
∣
∣
∣
∣
(3+2λ)
2
+(2+5λ)
2
2(3+2λ)−(2+5λ)+4−λ
∣
∣
∣
∣
∣
∣
=2
⇒6+4λ−2−5λ=2
29λ
2
+32λ+13
⇒−2λ+8=2
29λ
2
+32λ+13
⇒λ
2
+16−8d=29λ
2
+32λ+13
⇒28λ
2
+40λ−3=0⇒28λ
2
+42λ−2λ−3=0
14λ(2λ+3)−(2λ+3)=0
(14λ−1)(2λ+3)=0⇒λ=
14
1
or λ=
2
−3
L:x(3+
7
1
)+y(2+
14
5
)+4−
14
1
=0
44x+33y+55=0⇒
4x+3y+5=0
or x(3−3)+y(2−
2
15
)+4+
2
3
=0
⇒y(−11)+11=0⇒
y=1
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