Question

What are the critical points of the below equation?
0.33x^3+0.5x^2-6x
please give answer with steps​

Answer 1

Answer:

multiply by 100

33x³+50x²-600x

critical pts:value of x for which whole expression or value of function is 0

so,

33x³+50x²-600x=0

x1 = 3.57321

x2 = -5.08837

x3 = 0