What are the dimensions of a 60 – square meter rectangle that can be enclosed by 32 m of fencing material?
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Explanation :
Let the length be x and breadth be y
Given, area = 60 ( xy)
Perimeter = 32 { 2 (x + y)}
We have,
xy = 60 32 = 2 (x+y)
or x = 60/y ...1 16 = x+y ...2
Substituting value of x in ...2
16 = 60/y +y
By solving, we get y = 6 and x = 10
Hence the dimensions are 6m and 10m ans
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