Question

what are the dimensions of a and b in the relation: F=a+bn, where F is force and n is distance​

Answer 1

Answer:

The dimensions of a and b in the relation F = a + bx, where,F is the force and x is thedistance are a = [M L T^-2] , b= [M L^0 T^-2] a = [M L T^-2] ,b = [M L T^-2] a = [M^2 L T^-2] , b = [M L^0 T^-2] a = [M L T^-2] , b = [M^2 L^0 T^-2

Explanation:

Hope it helps

plzz follow me

mark me as branliest

Answer 2

Answer:

a= [L1 M1 T-2] and b= [L0 M1 T-2]

Explanation:

F=a+bn

According to principal of homogeneity,

F=a

Therefore,a= [L1 M1 T-2]

Similarly,

F=bn

[L1 M1 T-2]=b[L1]

[L1 M1 T-2]/[L1]=b

Therefore,b=[L0 M1 T-2]