Question

What are the dimensions of a rectangular field whose length is 4 meters more than its width and whose area is 96 square meters?

Answer 1

Answer:

Step-by-step explanation:

W = width

L = W + 4

Area = L x W

therefore A = (W+ 4)W = 96

= W^2 + 4W=96

= W^2 + 4W - 96 = 0

factorise to (W + 12) (W - 8)

W = -12 or W = 8. Therefore can only be W = 8.

length is 12 metres and width is 8 metres