Question

what are the dimensions of the cuboid whose volume is (x-2) (x-3)(x-5) ;x>5

Answer 1

Answer:

length >3

Width >2

and Height >0

Step-by-step explanation:

Given That volume =(x-2)(x-3)(x-5)=LxWxH

such that x>5

so

if we consider the Dimensions as

Length =(x-2)

width=(x-3)

and height=(x-5)

applying the condition x>5

We get x-2>5-2  ===>x-2>3, hence length >3

x-3>5-3  ====> x-3>2, hence width >2

and height =x-5>5-5  ===>x-5>0

so height >0