Question

What are the dimensions of the quantity l l/g ,l being the length and g the accelerated due to gravity?

Answer 1

Answer:

Hey mate plzz refer to the attachment

Answer 2

Answer:

Dimension of I = [L] and dimension of I/g = $\left[\mathrm{T}^{2}\right]$

Explanation:

In the question ‘’I’’ is said to be length which is denoted by ‘’L’’ therefore, dimensional formula of ‘’I’’ will be [L].

For I/G, first calculate dimensional formula for ‘’g’’

G = Velocity/Time  

First solve for velocity so V = distance/ time

V = L/T = $\mathbf{L} T^{-1}$

G = Velocity/time  

$\begin{array}{l}{=\mathrm{LT}^{-1} / \mathrm{T}} \\ {\mathrm{G}=\left[\mathrm{LT}^{2}\right]}\end{array}$

For I/G = dimension of I/ dimension of g

$=[\mathrm{L}] /\left[\mathrm{LT}^{2}\right]$ (Cancel both L)

$\begin{array}{l}{=1 / T^{-2}} \\ {I\left[G=\left[T^{2}\right]\right.}\end{array}$