What are the dimensions of the quantity l√l/g,l being the length and g the acceleration due to gravity
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Answered by
2
Answer:
The dimensions of l × √(l/g) are [L][T]
Explanation:
We have to find the dimensions of the quantity
l\times \sqrt{l/g}l×
l/g
We know that
Dimension of length l = [L][L]
Dimensions of acceleration due to gravity g = [LT^{-2}][LT
−2
]
Therefore, dimensions of l × √(l/g)
=[L]\times\sqrt{[L]/[LT^{-2}]}=[L]×
[L]/[LT
−2
]
=[L]\times\sqrt{[T^{2}]}=[L]×
[T
2
]
=[L]\times{[T^{2}]^{1/2}
=[L][T]=[L][T]
Therefore the dimensions of l × √(l/g) are [L][T]
Answered by
1
Answer:
the dimension of l is {L}
dimension of g is {LT^-2}
L√L/g
is L×L^1/2/{LT-2}
{L^3/2-1/T^-1}
{LT}..
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