Question

What are the dimensions of the quantity
l
$\sqrt{l \div g}$
, I being the length and g the
acceleration due to gravity?​

Answer 1

Answer:

[M^0L^0T^1]

Explanation:

l is length so its dimension=L^1

g has dimension L^1T^-2

so l÷g has dimension T^2

whose root has dimension T^1

Answer 2

Answer:

[T] or [M⁰L⁰T¹]

Explanation:

dimension of length = [M⁰LT⁰]

dimension of acceleration due to gravity = [M⁰L(T-²)]

=> dimension of √(l/g) = √ [L] ÷ { [L(T-2)] }

=> dimension of √(l/g) = √ [T²]

=> dimension of √(l/g) = [T]