What are the extrema of f(x)=(x−4)(x−5) on [4,5]?
Answers
Answered by
1
Soln:
f(x)=(x-4)(x-5)
=x(x-5)-4(x-5)
=x²-5x-4x+20
=x²-9x+20
Answered by
0
Hey dude
here is your answer
f(x) = x^2-9x+20
for extreme values put f'(x) =0
f'(x)= 2x-9=0. =>x=9/2
and f"(x)=2>0
so clearly it the function had minimum at x=2/9
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