Math, asked by tuesdayetaylor, 20 days ago

What are the factors of 17ab - 34a^2b+51ab^3

a. (2a - 3b^2)

b.(b)

c. (1 - 2b + 3a)

d. (17 - 34a + 51b^2)

e. (17)

f. (a)

g. (1 - 2a + 3b^2)

Answers

Answered by shifaalam
48

1 Answer

(b) 17ab.

The given factors can be written in expanded form as,

17abc = 17 × a × b × c.

34ab2 = 2 × 17 × a × b × b.

51a2b = 3 × 17 × a × a × b.

So, common factors in the above is 17 × a × b.

= 17ab.

Answered by tejaswinisinha1634
0

Step-by-step explanation:

The given factors can be written in expanded form as,

17abc 17 × axbxc.

34ab2 = 2 x 17 x a × b × b.

51a2b = 3 x 17 x ax ax b.

So, common factors in the above is 17 x a x

b.

= 17ab.

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