What are the factors of (2x + 3) cube + 64?
Answers
Answered by
0
Answer:
(2x+3)^3 + 64
(2x+3)^3 + (4)^3
(2x+3+4) {(2x+3)^2 -(2x+3)(4) + (4)^2}
(2x+7) [{(2x) ^2+2×2x×3+3^2} -24x+16]
(2x+7) (4x^2+12x +9- 24x +16)
(2x+7) (4x^2 - 12x+25)
Step-by-step explanation:
This equation was solved using the formula
a^3+b^3=(a+b) (a^2-ab+b^2)
Hope it helps......
Similar questions