what are the factors of (3a-1)^2-6a+2?
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Answered by
1
Answer:
(3a - 1) (3a - 3)
Step-by-step explanation:
(3a - 1)^2 - 6a + 2
= (3a - 1)^2 - 2 (3a - 1) [ Taken '2' common ]
= (3a - 1) (3a - 1 - 2) [ Taken ' 3a - 1 ' common ]
= (3a - 1) (3a - 3)
Answered by
0
Answer:
(3a-1)^2-6a+2
using identity (a-b)^2 = a^2+b^2-2ab
9a^2+1-6a-6a+2
9a^2-12a+3 is the answer
Step-by-step explanation:
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