Question

What are the factors of 6 whose sum is 3 root 2

Answer 1

Answer:

Hello There !

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Two zeros are 3+√2 , 3-√2

Sum of zeros (S) = 3+√2+3-√2 = 6 

product of zeros (P) = 3+√2(3-√2)

                                 = 9 -3√2+3√2-2

                                 = 7 

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Quadratic equation = k(x²-Sx+P)

Let k = 1

Quadratic equation = x²-6x+7 

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