Question

what are the factors of p^2+5p-36

Answer 1

Answer:

p=9,4

Step-by-step explanation:

p^2 + 5p -36 ( 1)

p^2 + 9p - 4p - 36

p(p+9) - 4(p+9)

now (p+9) (p-4)

take p+9=0 we get p=9

AND

TAKE p-4=0 we get p=4

HENCE THE VALUE OF p is 4 and 9

Answer 2

Answer:

$\Large\boxed{(P-4)(P+9)}$

Step-by-step explanation:

GIVEN:

p²+5p-36

To solve this problem, first you have to find the factors of p²+5p-36 from left to right numbers. Isolate by the p from one side of the equation.

SOLUTIONS:

First, you have to use distributive property by expanding expression.

$\Large\boxed{\textnormal{DISTRIBUTIVE PROPERTY FORMULA}}}$

$\displaystyle A(B+C)=AB+AC$

$\displaystyle (p^2-4p)+(9p-36)$

Factor it out by the p.

Used exponent rule.

$\Large\boxed{\textnormal{EXPONENT RULES FORMULA}}}$

$\displaystyle A^B^+^C=A^BA^C$

$\displaystyle PP=P^2$

Rewrite the problem down.

$\displaystyle PP-4P$

Common term of p.

$\displaystyle p(p-4)$

Factor it out by the 9.

Multiply.

$\displaystyle 4*9=36$

$\displaystyle 9p-9*4$

Common term of 9.

$\displaystyle 9(p-4)$

Rewrite the whole problem down again.

$\displaystyle P(P-4)+9(P-4)$

Solve.

Common term of p-4.

$\Large\boxed{(P-4)(P+9)}$

Therefore, the correct answer is (p-4)(p+9).