Math, asked by rishikakundu709, 7 months ago

what are the factors of x^2+2√3x-24 ​

Answers

Answered by bagkakali
1

Step-by-step explanation:

x^2+2√3x-24

=x^2+2.x.√3+3-3-24

=(x+√3)^2-27

=(x+√3)^2- (3√3)^2

=(x+√3+3√3) (x+√3-3√3)

=(x+4√3) (x-2√3)

Answered by UNKNOWNmind
0

Answer:

x^2+2√3x-24=0

x^2+4√3x-2√3x-24=0

x(x+4√3)-2√3(x+4√3)=0

(x-2√3)(x+4√3)=0

x=2√3,-4√3

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