Math, asked by shalini92, 1 year ago

What are the factors of x^3-8x^2+20x-13

Answers

Answered by Anonymous
1
(x-1) is one of the factors

shalini92: Actually I got that... But I need to more factors of it
shalini92: *two
Answered by Rishabhwastaken
1
Final result :

(x2 - 7x + 13) • (x - 1)
Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((x3) - 23x2) + 20x) - 13
Step 2 :

Checking for a perfect cube :

2.1 x3-8x2+20x-13 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-8x2+20x-13

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: x3-13
Group 2: -8x2+20x

Pull out from each group separately :

Group 1: (x3-13) • (1)
Group 2: (2x-5) • (-4x)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.
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