Math, asked by abhijit45, 11 months ago

What are the formulae of:

I) 1 + cos2x

II) 1 - cos2x

Answers

Answered by ranitiwari98
36

Answer:

formula of 1+cos2x= 2cos^2x

formula of 1-cos2x=2sin^2x

Step-by-step explanation:

hope it helps u

Answered by sourasghotekar123
0

Answer:

The formula is (I)2sin^{2}x\: and\:(II) 2cos^{2}x

Step-by-step explanation:

As per the data given in the question,

we have,

I) 1 + cos2x

= sin^{2}x+cos^{2}x +cos2x \:\:\:(as,\: sin^{2}x+cos^{2}x=1)\\= sin^{2}x+cos^{2}x+cos^{2}x-sin^{2}x\:\:\:(as,\: cos^{2}x-sin^{2}x=cos2x)\\=2cos^{2}x

II) 1 - cos2x

= sin^{2}x+cos^{2}x -cos2x \:\:\:(as,\: sin^{2}x+cos^{2}x=1)\\= sin^{2}x+cos^{2}x-(cos^{2}x-sin^{2}x)\:\:\:(as,\: cos^{2}x-sin^{2}x=cos2x)\\=2sin^{2}x

Hence the formula is (I)2sin^{2}x\: and\:(II) 2cos^{2}x

#SPJ2

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