Math, asked by bkiran2728, 14 days ago

what are the formulas in alzebra

Answers

Answered by pihusinha1605
0

Answer:

• a² – b² = (a-b)(a+b)

• (a+b)² = a² + 2ab + b²

• (a-b)² = a² – 2ab + b²

• a² + b² = (a-b)² +2ab

• (a+b+c)² = a²+b²+c²+2ab+2ac+2bc

• (a-b-c)² = a²+b²+c²-2ab-2ac+2bc

• a³-b³ = (a-b) (a² + ab + b²)

• a³+b³ = (a+b) (a² – ab + b²)

• (a+b)³ = a³+ 3a²b + 3ab² + b³

• (a-b)³ = a³- 3a²b + 3ab² – b³

• “n” is a natural number, an – bn = (a-b) (an-1 + an-2b +….bn-2a + bn-1)

• “n” is a even number, an + bn = (a+b) (an-1 – an-2b +….+ bn-2a – bn-1)

• “n” is an odd number an + bn = (a-b) (an-1 – an-2b +…. – bn-2a + bn-1)

(am)(an) = am+n (ab)m = amn

Answered by hansa01071980
0

Answer:

• a² – b² = (a-b)(a+b)

• (a+b)² = a² + 2ab + b²

• (a-b)² = a² – 2ab + b²

• a² + b² = (a-b)² +2ab

• (a+b+c)² = a²+b²+c²+2ab+2ac+2bc

• (a-b-c)² = a²+b²+c²-2ab-2ac+2bc

• a³-b³ = (a-b) (a² + ab + b²)

• a³+b³ = (a+b) (a² – ab + b²)

• (a+b)³ = a³+ 3a²b + 3ab² + b³

• (a-b)³ = a³- 3a²b + 3ab² – b³

• “n” is a natural number, an – bn = (a-b) (an-1 + an-2b +….bn-2a + bn-1)

• “n” is a even number, an + bn = (a+b) (an-1 – an-2b +….+ bn-2a – bn-1)

• “n” is an odd number an + bn = (a-b) (an-1 – an-2b +…. – bn-2a + bn-1)

(am)(an) = am+n (ab)m = amn

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