Question

what are the four numbers..they are consecutive ,their product is 24​

Answer 1

Explanation:

Let

the first number =x

${:}\longrightarrow$ the second number=(x+2)

${:}\longrightarrow$the third number=(x+3)

${:}\longrightarrow$the fourth number=(x+4)

Now,

• According to the question

${:}\longrightarrow$their product=24

${:}\longrightarrow$$x(x+2)(x+3)(x+4)=24$

${:}\longrightarrow$$(x (x+2)×x(x+4)+3 (x+4)=24$

${:}\longrightarrow$$({x}^{2}+2x)({x}^{2}+4x+3x+12)=24$

${:}\longrightarrow$$({x}^{2}+2x)({x }^{2}+7x+12)=24$

${:}\longrightarrow$${x}^{2}({x}^{2}+7x+12)+2x ({x}^{2}+7x+12)=24$

${:}\longrightarrow$${x}^{4}+{7x}^{3}+{12x}^{2}+{2x}^{3}+{14x}^{2}+24x =24$

${:}\longrightarrow$${x}^{4}+{7x}^{3}+{2x}^{3}+{12x}^{2}+{14x}^{2}+24x=24$

${:}\longrightarrow$${x}^{4}+{10x }^{3}+{16x}^{2}+24x=24$

${:}\longrightarrow$${x}^{4}+{10x}^{3}+{16x}^{2}+24x-24=0$