Question

What are the frequency and wavelength of a photon emitted during a transition from n = 5 state to the n = 2 state in the hydrogen atom?

Answer 1

λ=433.93669nm

Explanation:

λ=hcEpEp

is the energy of photon.

Since,

Ep=2π2meK2Z2e4h2(1n22−1n25)K=14πε0,n2=2,n5=5,Z=1λ=800⋅h3⋅c⋅ε2021⋅me⋅e4

Putting in the values of physical constants

λ=433.93669nm

Here,

λ=

wavelength of photon

h=

Planck's constant

me=

mass of electron

c=

speed of light in vacuum

e=

elementary charge

Z=

Atomic No. [1 for hydrogen]

Answer 2

◇◇ Refer to the attachment above for your answer ◇◇

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