Chemistry, asked by bhimashankarthore428, 1 year ago

What are the frequency and wavelength of a photon emitted during a transition from n=5 state to the n=2 state in the hydrogen atom?​

Answers

Answered by kinsjackson
3

Answer:

1/wavelength=RH(1/ni²-1/nf²)

                     =109677(1/5²-1/2²)

                      =109677(21/100)

                      =2303217/100

                      =23032.17

therefore, wavelength=1/23032.17 m

frequency=c/wavelength

                =3.08 x 10^{8}/1/23032.17

                 =3.08 x 23032.17 x 10^{8}  

                = 70939.0836 x 10^{8} Hz

HOPE IT HELPS YOU

Answered by mugdha10
2

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