what are the frequency and wavelength of a photon emitted during a transition from n=4 to the n=3 state in the hydrogen atom?
Answers
Answer:
frequency and wavelength of a photon emitted during a transition from n=4 to the n=3 state in the hydrogen atomडैभेढेढेत
Answer:wavelength(λ) = 144/7R
frequency,(nu)= c/λ
=21R x 10^8/144
Explanation:
(GIVEN) its given that the atom is hydrogen.therefore, the atomic no.(z)=1,the state from which the electron is initially starting (n2) = 4, the state in which the electron finally lands to emit radiation (n1)= 3.
solution - the wavelength can be calculated using the eqn., - 1/λ = R(z^2) x (1/n1 ^2 - 1/n2^2)
1/λ = R x 1 (1/9 - 1/16)
1/λ=R(16-9/144)
1/λ=7R/144
Hence , wavelength(λ) = 144/7R
and frequency,(nu)= c/λ
= 3x10^8/144/7R
=21R x 10^8/144