Question

What are the frequency and wavelength of a photon emitted during a transition from n = 4 state to the n = 2 state in the hydrogen atom?

Answer 1

By Rydberg equation,

Wave number = R ( 1 / n1^2 - 1 / n 2^2)

Wave number or 1 / Wavelength = 109677 * ( 1 / 2^2 - 1 / 4^2

Wave number or 1 / Wavelength = 109677 *( 1 / 4 - 1/ 16)

Wave number or 1 / Wavelength = 109677 *(4 - 1 /16)

Wave number or 1 / Wavelength = 109677 *(3 / 16)

Wavelength = 16 / 329031

WAVELENGTH = 4.86 m

FREQUENCY = Speed of light / wavelength

FREQUENCY = 3 * 10^8 / 4.86

FREQUENCY = 61728395. 1 Hz