Question

what are the frequency and wavelength of photon is emitted during a transition from N = 5 to n = 2 in the hydrogen atom R = 2.18 into 10 to the power minus 8​

Answer 1

Explanation:

Here, it is given that n1=2 and n2=5

Since, 1/lambda=R(1/n1^2-1/n2^2)

=R(1/2^2-1/5^2)

=R(1/4-1/25)

=R('25-4'/100)

1/lambda =R(21/100)

Therefore, lambda =100/21*1/R

=100/21*903 A

=100*43A

=4300 A