Math, asked by estherjoseph583, 7 months ago

What are the identities of 71^2

Answers

Answered by himuik1111
0

Answer:

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Answered by hastipatil
0

Answer:

5041

Step-by-step explanation:

=(70+1)^2

(a+b)^2=a^2+b^2+2ab

putting=(70)^2&b=1

=(70)^2+(1)^2+2(70)(1)

=4900+1+140

=5041

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