Math, asked by kabhishekh5232, 9 months ago

What are the largest four digit and smallest three digit number divisible by 6,15, 21 &24? A)9235,420 b)9980,840 c)9240,840 d)9999,999?

Answers

Answered by kartik2507
0

Answer:

c) 9240, 840

Step-by-step explanation:

LCM of 6, 15, 21 & 24 is 840

therefore 840 is the least common multiple of 6, 15, 21 & 24

840/6 = 140

840/15 = 56

840/21 = 40

840/24 = 35

largest 4 digits number is 9999

largest 4 digits number multiple of 6, 15, 21 & 24 is

840 × 11 = 9240

hope you get your answer

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