Math, asked by EniH, 3 months ago

WHAT ARE THE LAST TWO DIGITS OF 7^2018?
(7^2018= seven raised to power 2018)
If you do not mind, could you please explain step by step as I am quite lost (If not it is okay to mark just the answer, don't worry)
Thank you in advance!

Answers

Answered by pritamwaghmare5c
1

Answer:

Step-by-step explanation:

Hii mate ^_^

=7⁴ⁿ⁺² where n=504.

Last two digits of 2²⁰¹⁸ = 49.

Answered by anjalipandeybbu
2

Answer:

I hope you have got your answer.

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