WHAT ARE THE LAST TWO DIGITS OF 7^2018?
(7^2018= seven raised to power 2018)
If you do not mind, could you please explain step by step as I am quite lost (If not it is okay to mark just the answer, don't worry)
Thank you in advance!
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Answered by
1
Answer:
Step-by-step explanation:
Hii mate ^_^
=7⁴ⁿ⁺² where n=504.
Last two digits of 2²⁰¹⁸ = 49.
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2
Answer:
I hope you have got your answer.
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