Question

what are the last two digits of 7 power 45​

Answer 1

Answer:

The last two digits of 74 are 01. Thelast two digits of powers of 7 go in a cycle - 07, 49, 43, 01. So, the last two digits of 745 are 07.

Answer 2

Answer:

The last two digit of 7 power 45 is 07.

Step-by-step explanation:

We have to find  the last two digits of 7 power 45​.

Let's see what happens.

7^1=7

72=49 unit position=9

unit place=3 73=343

74=xxx1 unit location=1

Now, if you take 75 units, the place will be 7, and 76 units will be 9, and so on.

This cycle will be repeated every time a multiple of 4 is reached.

So for 7^45

Find the remainder of 45 by dividing it by four.

It will be 1

As a result, its unit position will be the same as 7 power 1.

That is seven.

As a result, 7 is the correct answer.

Hence, The last two digit of 7 power 45 is 07.

#SPJ5