What are the last two digits of 72008?
01
21
41
61
Answers
Answered by
3
Answer:
The correct option is A.
Explanation:
Observe the pattern:
71 = 7
72 = 49
73 = 343
74 = 2401
75 = 16807
76 = 117649
The last two digits are repeating.
For every power of the form 4n, the last two digits are 01.
Answered by
0
Answer:
01..................... ...... . ......
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