Math, asked by RaniRaj24, 1 year ago

What are the laws of radicals

Answers

Answered by pihu08
10


hope its helps u mark me as A brainlist



Attachments:

RaniRaj24: U r correct but somewhat little problems to understand me....
RaniRaj24: It is not a clear answer....
Royal213warrior: yes !!!! yes !!!!
Royal213warrior: that was what i was talking about
Answered by Royal213warrior
14
===================================
Hey, Mate....
===================================
If 'a > 0', 'b > 0' and 'n' is a positive rational number, then
===================================
1st law....

 (\sqrt[n]{a }) \: ( \sqrt[n]{b} ) \: = \: \sqrt[n]{ab}
===================================
2nd law....

 \sqrt[n]{a} \div \: \sqrt[n]{b} \: = \: \sqrt[n]{a \div b}
===================================
3rd law....

 \sqrt[m]{ \sqrt[n]{a} } \: = \: \: \sqrt[mn]{a} \: \: = \sqrt[n]{ \sqrt[m]{a} }
===================================
4th law....

 \sqrt[n]{a {}^{p} } \: \: = \: \: a {}^{p \: or \: n} \: \: \: and \: \: \: \sqrt[n]{a {}^{p} } \: \: = \: \: \sqrt[n]{ \sqrt[m]{(a {}^{p) {m}^{} } } }
===================================
Hope it helped you.....
===================================
Please market my answer as BRAINLIEST....
===================================

RaniRaj24: Thanks Royal213warrior...
RaniRaj24: It is a correct answer thanks for my help....
Royal213warrior: your welcome
Similar questions