Question

what are the nature roots of the following quadratic equation? x²+x-6=0​

Answer 1

Solve with the Quadratic Formula

Let's solve your equation step-by-step.

x2+x−6=0

For this equation: a=1, b=1, c=-6

1x2+1x+−6=0

Step 1: Use quadratic formula with a=1, b=1, c=-6.

x=

−b±√b2−4ac

2a

x=

−(1)±√(1)2−4(1)(−6)

2(1)

x=

−1±√25

2

x=2 or x=−3

Answer:

x=2 or x=−3

Answer 2

Answer:

distinct roots...is the correct answer because d us smaller than 0