What are the next three terms of the following geometric sequence: 3/2, 3/4, 3/8...
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Answered by
1
So here we see that
a=first term=3/2
r=common ratio=(3/4)/(3/2)=1/2
So,
ai=a(r^(n-1))
a4=3/2*(1/2)^3=3/16
a5=3/2*(1/2)^4=3/32
a6=3/2*(1/2)^5=3/64
Hope this helps you and please mark it as the brainliest
Cheers :)
a=first term=3/2
r=common ratio=(3/4)/(3/2)=1/2
So,
ai=a(r^(n-1))
a4=3/2*(1/2)^3=3/16
a5=3/2*(1/2)^4=3/32
a6=3/2*(1/2)^5=3/64
Hope this helps you and please mark it as the brainliest
Cheers :)
Answered by
1
I hope it helps you
Please mark my answer as brainlist answer
Please mark my answer as brainlist answer
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