Question

What are the number of protons, neutrons and electrons in 59 Co 27 and 108 Ag 47 ?

Answer 1

C27o59Number of proton = Atomic number =27Mass number = number of proton + number of neutron = 59Number of neutrons = 59 − 27 = 32Number of electrons = number of proton = 27A47g108Number of proton = Atomic number =47Mass number = number of proton + number of neutron = 108Number of neutrons = 108 − 47 = 61Number of electrons = number of proton = 47

Answer 2

1. co
2. Ag
3. guse and tell the answer