Question

What are the number of substitution products when metabromo anisole is treated with knh2/nh3

Answer 1

Answer:

knh2/NH3 = 24%₹4600 is the correct answer

Answer 2

The quantity of substitution products produced while treating metabromo anisole with knh2/nh3

Formation :

Ammonia and potassium react, and the result is potassium amide. Usually, a catalyst is required for the reaction.

Each potassium center in KNH2/NH3 is linked to two amido ligands and four ammonia ligands, and all six of these ligands are capable of bridging to other potassium centers. A chain of potassium ions with six coordinates is the end product.

Reason:

When the nucleophile (-NH2) attacks Br, there are three possible bond formation positions: ortho, para, and meta.

• These positions are depicted in the structures 2, 3, and 1 , respectively.

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