Math, asked by jyothimanepalli71, 19 days ago

what are the number of zeroes of the polynomial f(x)=[x-3]whol square+4

Answers

Answered by Jhachandrashekhar841

1

Answer:

(x - 3)²+ 4 =0
(x-3)²+2²=0

Answered by anamikabp9

0

Answer:

x-6.5

Step-by-step explanation:

if(x) =[x-3] whole square +4

= x whole square -3 whole square+4

= x whole square - 9+4

= x whole square - 13

= x-13/2

= x -6.5

x = x - 6.5

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