Question

What are the odds in favour of throwing at least 7 in a single throw with two dice?

Answer 1

1, 3 ,5 is the answer

Answer 2

When two dice are rolled together the possible outcomes n =6*6=36
Let E be the event of getting total count on upper faces at least 7 (7,8,9,10,11,or 12) is m= 6+5+4+3+2+1=21
(7 occurs 6 times, 8 occurs 5,9occurs 4,10 occurs 3, 11 occurs 2, and 12 occurs 1 time respectively)
Therefore the probability of success P(E) =m/n=21/36=7/12
The odds in favour of an event 7:5