Question

what are the ordered pairs satisfying equation 2x +3y =10​

Answer 1

Answer:

2x + 3y < 10 would hold true for values of + ve integers at , (1,1), ( 2,1),(1,2) ,(3,1)so total 4 .. IMO D..Every point in the blue shaded region satisfies the inequality 2x+3y<10.

This is found by graphing the equation 2x + 3y = 10. The line of the equation is not included, because points like (5,0) will equal 10, but instead they should be less than 10. The drawing convention is a dotted line is not included in the solution set, but a solid line is.

However, if you had asked: “How many ordered pairs of whole numbers satisfy the inequality 2x+3y<10?” you would have a finite answer. 12 ordered pairs of whole numbers: (0,0) (0,1) (0,2) (0,3)

have a finite answer. 12 ordered pairs of whole numbers: (0,0) (0,1) (0,2) (0,3) (1,0) (1,1) (1,2) (2,0) (2,1) (3,0) (3,1) (4,0)