what are the other members of pythagorean triplet of 63
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Answered by
16
the no.s are 16,65,63 by using the method 2m,m²+1,m²-1⇒m=8 and thus the no.s are 16, 65, 63
DhruvkundraiMessi:
please mark me as brainliest
how is m=8
by putting 65 in the place of m square +1
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thanks
Answered by
12
As we know 2m, m²+1, m²-1 form a Pythagorean triplet for any number, m>1
Let m= 8
2m= 2×8= 16
m²+1= 8²+1= 64+1=65
m²-1= 8²- 1= 64- 1= 63
hence the other members are 16, 65,63
Let m= 8
2m= 2×8= 16
m²+1= 8²+1= 64+1=65
m²-1= 8²- 1= 64- 1= 63
hence the other members are 16, 65,63
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