What are the partial pressure in milibars of oxygen and nitrogen in dry mixture of 21% o2 and 79% n2 at 1 atm?
Answers
Answered by
0
You can easily calculate the partial pressure of oxygen keeping in mind the definition of partial pressure.
First of all You have the find out the mole fraction of the oxygen and we know that mole fraction can be calculated from percentage composition of the gas divided by the total percentage of all gases
So here oxygen is 21% = mole fraction of 21 % oxygen =21/100 = 0.21
Here total pressure is give which is =750mm of Hg
Partial pressure of oxygen will be = 750 *0.21 = 157.5 mm of Hg .
So partial pressure of oxygen will be 157.5 mmHg
Similar questions
Math,
5 months ago
English,
5 months ago
Chemistry,
5 months ago
Computer Science,
10 months ago
English,
10 months ago