what are the point where the graph of p(x)=xsquare+x-12
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Answered by
11
solving given quadratic equation
x²+x-12 =0
x² +4x -3x -12=0
x(x+4) -3(x+4) =0
x-3=0 n x+4=0
x=3 , x= -4
x= (3,-4)
the points are3 , -4
x²+x-12 =0
x² +4x -3x -12=0
x(x+4) -3(x+4) =0
x-3=0 n x+4=0
x=3 , x= -4
x= (3,-4)
the points are3 , -4
Answered by
2
points are -4 and 3
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hope it helped u
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