Question

what are the points on y axis whose perpendicular distance from the x/3-y/4=1
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Answer 1

Step-by-step explanation:

Let the required point is A(0,p).

So, required points will be (0,323) and (0,-83).

Answer 2

Answer:

Let (0,b) be the point on the y-axis whose distance from line

3

x

+

4

y

=1 is 4 units.

The given line can be written as 4x+3y−12=0....(1)

Thus using distance formula,

4=

4

2

+3

2

∣4(0)+3(b)−12∣

⇒4=

5

∣3b−12∣

⇒20=∣3b−12∣

⇒20=±(3b−12)

⇒20=(3b−12) or 20=−{3b−12}

⇒3b=20+12 or 3b=−20+12

⇒b=

3

32

or b=−

3

8

Thus, the required points are (0,

3

32

)and(0,−

3

8

).

Step-by-step explanation:

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