Question

what are the points where the graph of P(x) = X2 + X - 12

Answer 1

x²+x-12
p-12 s=1
x²-4x+3x-12
x(x-4)+3(x-4)
(x+3)(x-4)
x=-3  x=4

Answer 2

X2+X-12
Factors of -12
It would be -3 × 4
X2+4x-3x-12=0
X(x+4)-3(x+4)=0
(x-3=0) (x+4=0)
X=3 and X= -4