Question

What are the points where the graph p(x)= x2 + x - 12 intersects the x axis?

Answer 1

x^2+x-12=0
x^2+4x-3x-12=0
p(x) intersects x axis at -4;3

Answer 2

the point where y=p(x) intersect the x-axis is at y=0

x^2+x-12=0
x^2+4x-3x-12=0
x(x+4)-3(x+4)=0
(x-3)(x+4)=0

at x =3,-4 it will intersect y-axis