what are the possible expressions for the dimensions of a rectangle whose area is (35y^2 + 13y - 12)
Answers
Answered by
4
Hi , factorise 35y^2+13y-12
35y^2+28y-15y-13
7y(5y+4)-3(5y+4)
(7y-3)(5y+4)
one possible answer is length is equal to (7 y -3), breadth is equal to (5y+ 4) answer.
35y^2+28y-15y-13
7y(5y+4)-3(5y+4)
(7y-3)(5y+4)
one possible answer is length is equal to (7 y -3), breadth is equal to (5y+ 4) answer.
thegreatkhali:
thanks
Answered by
8
Given Area:
35y²+13y-12
To Find :
Length and Breadth
Solution :
Factorising 35y²+13y-12
[By mid term spilting]
35y²+13y-12
35y²+28y-25y-12
7y(5y+4)-3(5y+4)
(5y+4) (7y-3)
Length = 7y-3
Breadth = 5y+4
35y²+13y-12
To Find :
Length and Breadth
Solution :
Factorising 35y²+13y-12
[By mid term spilting]
35y²+13y-12
35y²+28y-25y-12
7y(5y+4)-3(5y+4)
(5y+4) (7y-3)
Length = 7y-3
Breadth = 5y+4
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